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Given electrode potentials are , Fe^(3+)...

Given electrode potentials are , `Fe^(3+) + e to Fe^(2+), E^@ = 0.771V " " I_2 + 2e to 2I^(-), E^@ = 0.536 V`,
`E^@` cell for the cell reaction, `2Fe^(3+) + 2I^(-) to 2Fe^(2+) + I_2` is

A

`0.536 - 0.771 = - 0.236 V`

B

`(0.771 - 0.5 xx 0.536) = 0.503 V`

C

`0.771 - 5.36 = 0.235V`

D

`(2 xx 0.771 - 0.536) = 1.006V`

Text Solution

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The correct Answer is:
C
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