The weight of solute present in 200 ml o...

The weight of solute present in 200 ml of 0.1 M `H_(2)SO_(4)`

3.92 g

4.9 g

1.96 g

2.45 g

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The ammonia evolved from the treatment of 0.30g of an organic compound for the estimation of nitrogen was passed in 100ml of 0.1 M H_(2)SO_(4) . The excess acid required 20ml of 0.5M NaOH solution for complete neutralisation . The organic compound is:

A mmonia is highly soluble gas in water and gives a alkaline solution of NH_(4) OH . What volume of NH_(3) gas at STP will be required to the passed in 100 mL of 0.5 M H_(2) SO_(4) to bring down its strength to 0.25 M ? (For titrations with aqueous NH_(3) , it is assumed that NH_(4) OH dissociates to 100% extent) a. 2.24 L b. 1.68 L c. 1.12 L d. 0.56 L

What should be the normality of a solution prepared by diluting 250 ml of 0.4 NH_(2)SO_(4) with 1000 ml of water?

The milliequivalents in 60 ml of 4.0 M H_(2)SO_(4) is :

Molarity of 0.2 N H_(2) SO_(4) is

During nitrogen estimation present in an organic compound by Kjeldahl.s method, the ammonia evolved from 0.5 g of the compound in Kjeldahl.s estimation of nitrogen neutralised 10 ml of 1 M H_(2)SO_(4) . Find the percentage of nitrogen in the compound.

Calculate pH of 0.005 M H_(2)SO_(4) .

Calculate the pH of 0.125M of H_(2)SO_(4) .

A bottle of commercial sulphuric acid (d = 1.787 g mL^(-1)) is 86% by weight. a. Whatis molarity of the acid? b. What volume of the acid has to be used to make 1 L of 0.2 M H_(2) SO_(4) ? c. What is the molality of the acid?

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