Home
Class 12
PHYSICS
A wire of resistance 10 Omega is bent to...

A wire of resistance `10 Omega` is bent to form a circle. P and Q are points on the circumference of the circle dividing it into a quadrant and are connected to a Battery of 3 V and internal resistance `1 Omega` as shown in the figure. The currents in the two parts of the circle are

Promotional Banner

Similar Questions

Explore conceptually related problems

A wire of resistance 4 Omega is bent to form a circle. The resistance point A and B will be

A thin wire of resistance 4Omega is bent to form a circle. The resistance across any diameter is

A wire of resistance 5 Omega is bent in the form of a closed circle. Find the resistance across the diameter of the circle.

A network of resistor is connected to a 16 V battery with internal resistance of 1 Omega , a shown in fig. Obtain the current in each resistor.

A certain length of a uniform wire of resistance 12Omega is bent into a circle and two points, a quarter of circumference apart, are connected to a battery of emf 4 V and internal resistance 1Omega . Find the current in the different parts of the circuit.

A certain length of a uniform wire of resistance 12Omega is bent into a circle and two points, a quarter of circumference apart, are connected to a battery of emf 4 V and internal resistance 1Omega . Find the current in the different parts of the circuit.

A 10 V cell of negligible internal resistance is connected in parallel across a battery of emf 200 V and internal resistance 38 Omega as shown in the figure. Find the value of current in the circuit.

A wire of resistance 10Omega is bent to form a complete circle. Find its resistance between two diametrically opposite points.