A line is of length 10 units and one of its ends is `(-2, 3)`. If the ordinate of the other end is 9, prove that the abscissa of the other end is `6` or `-10`

A line of length 10 units has one end at the point (-3,2). If the ordinate of the other end is 10, show that the abscissa will be 3 or -9.

A line is of length 10 unit and one end is at (2, -3). If the abscissa of the other end is 10. Then its ordinate is

A line is of the length 10 units and one end is at (2,-3). If the abscissa of the other end is 10, then find its ordinate.

The length of a line segment is sqrt(29) units. If one end is at (-3,5) and the ordinate of the other end is 7 , show that the absciss is either 2 or - 8 .

The length of a line segment is of 10 units and the coordinates of one end-point are (2,-3) . If the abscissa of the other end is 10, find the ordinate of the other end.

The length of a line segment is of 10 units and the coordinates of one end-point are (2,-3). If the abscissa of the other end is 10, find the ordinate of the other end.

The length of a line segment is of 10 units and the coordinates of one end-point are (2,-3)dot If the abscissa of the other end is 10, find the ordinate of the other end.

The length of a line segment is 10 units . If the coordinates of its one end point are (2,-3) and the abscissa of the other end point is 10, then its ordinate is . . . . .

One end of the diameter of a circle is (-2, 5). Find the co-ordinates of the other end of it, if the centre of the circle is (2, -1).