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cot (A-B) = (cotAcotB+1)/(cotA-cotB)...

`cot (A-B) = (cotAcotB+1)/(cotA-cotB)`

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cot(A-B)=(cotA.cotB+1)/(cotB-cotA)

cot(A-B)=(cotA.cotB+1)/(cotB-cotA)

Knowledge Check

  • If A+B+C=180^@ , then (cot A +cotB +cotC)/(cot A cotBcotC) is equal to

    A
    1
    B
    `cot A cos B cot C`
    C
    `-1`
    D
    0

  • If A+B+C =180^@ ,then cotA+cotB+cot C)/(cot A cot B cot C) is equal to

    A
    1
    B
    cot A cot B cot C
    C
    -1
    D
    0

    • Similar Questions

    Explore conceptually related problems

    Prove that : cot (A-B)= (cotA cot B+1)/(cotB -cotA) .

    Prove that- cot(A+B)=(cotA.cotB-1)/(cotA+cotB)

    cot(A+B)=(cotA.cotB-1)/(cotB+cotA)

    Prove that : cot (A+B)= (cotA cot B-1)/(cotB + cotA) .

    If A+B+C=pi , prove that : (cotB+cotC) (cotC+cotA) (cotA+cotB)=cosecA cosecB cosecC

    If A+B+C=pi , prove that : (cotB+cotC) (cotC+cotA) (cotA+cotB)=cosecA cosecB cosecC

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