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An element X has the following isotopic ...

An element X has the following isotopic composition `""^(200)X` = 90 %, `""^(199)X`=8 % and `""^(202)` X=2 %, The weighted average atomic mass of the element X is closest to

A

201u

B

202u

C

199u

D

200u

Text Solution

Verified by Experts

The correct Answer is:
D
`=((200 xx 90) + (199xx8) + (202xx2))/100 =199.96=200u`
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