The mass of a gas that occupies a volume of 612.5 ml at room temperature and pressure (`25^(@)`C and 1 atm pressure) is 1.1 g. The molar mass of the gas is

Options

A. 66.25 g `mol^(-1)`
B. 44 g `mol^(-1)`
C. 24.5 g `mol^(-1)`
D. 662.5 g `mol^(-1)`

Answer

B

Explanation

No. of moles of a gas that occupies a volume of 612.5 ml at room temperature and pressure (`25^(@)`C and 1 atm pressure)
`612xx10^(-3)L//24.5molL^(-1)`
0.025moles
We know that,
Molar mass=Mass no. /no. of moles
1.1g/0.025 mol=44g `mol^(-1)`