How many moles of ethane is equaired to produce 44 g of `CO_(2(g))` after combustion.

Explanation

`underset("Ethane")(C_(2)H_(6)) + 3xx1/2 O_(2) to underset("Carbon dioxide")(2CO_(2))+3H_(2)O`
1 mole of Ethane `overset("Combustion")(to)` 2 moles of `CO_(2)`
`:.` 1 mole of `CO_(2)`
2 moles of `CO_(2)` is produced by 1 mole of ethane.
1 mole of `CO_(2)` will be produced by = ?
`:.`To produce 1 mole of `CO_(2)` , the required mole of ethane is =`1/2 xx 1` = 0.5 mole of ethane.