`Cl_(2)` changes to `Cl^( -)` and `ClO^(-)` in cold NaOH. Equivalent mass of `Cl_(2)` will be.

Options

A. Molar mass/2
B. Molar mass/1
C. Molar mass/3
D. `2xx` Molar mass/2

Answer

A

Explanation

`Cl_(2) to 2Cl^(-) + 2e^(-)`
`Cl_(2) overset(NaOH)(to) 2ClO^(-) + 2e^(-)`
`:.` Equivalent mass=`(" Molar mass")/("No. of electrons lost")=("Molar mass")/2`