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Equivalent mass of KMnO(4) in acidic med...

Equivalent mass of `KMnO_(4)` in acidic medium, concentrated alkaline medium and dilute basic medium respectively are M, M, M. Reduced products can be

A

`MnO_(2), MnO_(4)^(-) , Mn^(2+)`

B

`MnO_(2), Mn^(2+), MnO_(4)^(2-)`

C

`Mn^(2+), MnO_(2), MnO_(4)^(2-)`

D

`Mn^(2+), MnO_(4)^(2-), MnO_(2)`

Text Solution

Verified by Experts

The correct Answer is:
C

`MnO_(4)^(-) + 8H^(+) + 5e^(-) to Mn^(2+) + 4H_(2)O`(acidic medium)
`MnO_(4)^(-) + 4H^(+) + 3e^(-) to MnO_(2) + 2H_(2)O`(concentrated basic medium)
`MnO_(4)^(-) + e^(-) to MnO_(4)^(2-)`(dilute basic medium)
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