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20.0 g of a magnesium carbonate sample d...

20.0 g of a magnesium carbonate sample decomposes on heating to give carbon dioxide and 8.0 g magnesium oxide. What will be the percentage of purity of magnesium carbonate in the sample?

A

60

B

84

C

75

D

96

Text Solution

Verified by Experts

The correct Answer is:
B
`MgCO_(3) overset(Delta)(to) MgO + CO_(2)uarr`
84 g of `MgCO_(3)` gives 40 g of MgO. (100% purity)
20g of `MgCO_(3)` will give `=(40xx20)/84=9.52g`
9.52g of MgO is given by 100% pure `MgCO_(3)`.
8.0 g of MgO will be given by=`(100xx8)/9.52=84.03%`
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