How many molecules are present in 32 g of methane?

Options

A. `2xx6.023xx10^(23)`
B. `6.023xx10^(23)//2`
C. `6.023xx10^(-23)`
D. `3.011xx10^(23)`

Answer

A

Explanation

Methane `(CH_(4))` -Molar mass=12+4=16g
16 g contains `6.023 xx 10^(23)` molecules.
32 g of methane will contain =`(6.022xx10^(23))/cancel(16)xxcancel(32^(2))=2xx6.023xx10^(23)`