Number of atoms in 4.25 g of ammonia is

Answer

A, B, C

Explanation

Ammonia = `NH_(3)` (4 atoms)
Molecular mass = 14 + 3 = 17
17 g of Ammonia contains `6.023 xx 10^(23)` atoms
`:.`4.25 g of Ammonia will contain =`(6.023xx10^(23))/17xx 4.25 = 1.5055 xx 10^(23)` molecules.
`:. 1.5055 xx 10^(23)` molecules will contain `4 xx 1.5 xx 10^(23) = 6 xx 10^(23)` molecules.