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7.5 g of a gas occupies a volume of 5.6 ...

7.5 g of a gas occupies a volume of 5.6 litres at `0^(@)C` and 1 atm pressure. The gas is

Text Solution

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22.4 litres = 1 mole
5.6 litres =`1/22.4 xx 5.6` = 0.25 mole
NO = molar mass = 14 + 16 = 30 g =1 mole
`N_(2)O` = molar mass = 28 + 16 = 44 g =1 mole
CO = molar mass =12+16 = 28 g =1 mole
`CO_(2)` = molar mass =12 +32 = 44 g =1 mole
Among the four gases, 0.25 mole = 7.5 g is equal to NO gas.
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