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The mass in grams of 0.45 mole of Ca^(2+...

The mass in grams of 0.45 mole of `Ca^(2+)` ions

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The correct Answer is:
A

Ca = Atomic mass = 40
` Ca to Ca^(2+) + 2e^(-)`
41 g of Ca = 1 mole (for `Ca^(2+)` = Atomic mass remains same)
1 mole of `Ca^(2+)` = 40 g
`:.` 0.45 mole of `Ca^(2+)=40/1xx0.45=18g`
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