When 22.4 litres of `H_(2)` (g) is mixed with 11.2 litres of `Cl_(2)`(g), each at 273 K at 1 atm the moles of HCl (g). formed is equal to

Answer

A

Explanation

`H_(2) + Cl_(2) to 2HCl`
22 liters +11.2 litres
1 mole + 1/2 mole = 1 mole of HCl and 1/2 mole of `H_(2)` is remained