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The volume of HCI gas weighing 73 g at S...

The volume of HCI gas weighing 73 g at STP is

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The correct Answer is:
A, B, C, D
HCl = Molar mass = 1 + 35.5 = 36.5 g
36.5 g of HCl occupies `2.24 xx 10^(-2) m^(3)` .
`:.` 73 g of HCI at STP will occupy `(2.24xx10^(-2))/cancel(36.5) xx cancel(73^(2))=4.48xx10^(-2)m^(3)`.
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