If ten volumes of dihydrogen gases react with five volumes of dioxygen gases that, how many volumes of water vapour would be produced ?

Explanation

`underset(2 volumes)(2H_(2(g))) + underset(1 volume)(O_(2(g))) rarr underset(2 volumes)(2H_(2)O)`
Thus 2 volumes of `H_(2)` reacts with 1 volume of `O_(2)` to produce 2 volumes of `H_(2)O_((g))`.
`:.` 10 volumes of `H_(2)` would react with 5 volumes of `O_(2)` to produce 10 volumes of `H_(2)O_((g))` , Thus 10 volumes of `H_(2)O` will be produced.