Home
Class 11
CHEMISTRY
Define equivalent mass of an reducing ag...

Define equivalent mass of an reducing agent.
How would you determine the equivalent mass of Ferrous sulphate?

Text Solution

Verified by Experts

The equivalent mass of a reducing agent is the number of parts by mass of the reducing agent which is completely oxidised by 8 parts by mass of oxygen or one equivalent of any oxidising agent.
Ferrous sulphate is a reducing agent.
`2FeSO_(4)+H_(2)SO_(4)+[O]rarrFe_(2)(SO_(4))_(3)+H_(2)O`
16 parts by mass of oxygen oxidised 304 parts by mass of `FeSO_(4)`
`:.` 8 parts by mass of oxygen will oxidise `316/80 xx8` parts by mass of ferrous sulphate = 152
The equivalent mass of ferrous sulphate (anhydrous) = 152.
The equivalent mass of crystalline ferrous sulphate is `(FeSO_(4)*7H_(2)O)`=152+156=278
The equivalent mass of crystalline ferrous sulphate = 278.
Promotional Banner

Topper's Solved these Questions

  • BASIC CONCEPTS OF CHEMISTRY AND CHEMICAL CALCULATIONS

    FULL MARKS|Exercise Additional Questions Solved(3-Mark Questions)|27 Videos
  • ALKALI AND ALKALINE EARTH METALS

    FULL MARKS|Exercise Additional Questions Solved|224 Videos
  • BASIC CONCEPTS OF ORGANIC REACTIONS

    FULL MARKS|Exercise Additional Questions Solved (5-Marks Question)|10 Videos

Similar Questions

Explore conceptually related problems

The equivalent mass of ferrous oxalate is

Define equivalent mass of an oxidising agent How would you calculate the equivalent mass of potassium permanganate?

The equivalent mass of NaCl is

Calculate the equivalent mass of hydrated ferrous sulphate.

FULL MARKS-BASIC CONCEPTS OF CHEMISTRY AND CHEMICAL CALCULATIONS -Additional Questions Solved(5-Mark Questions)
  1. Balance the following equation by ion-electron method.

    Text Solution

    |

  2. Define equivalent mass of an oxidising agent How would you calculat...

    Text Solution

    |

  3. Define equivalent mass of an reducing agent. How would you determin...

    Text Solution

    |

  4. A compound on analysis gave the following percentage composition: C = ...

    Text Solution

    |

  5. A laboratory analysis of an organic compound gives the following mass ...

    Text Solution

    |

  6. An insecticide has the following percentage composition by mass. 47.5 ...

    Text Solution

    |

  7. An organic fruit smelling compound on analysis has the following compo...

    Text Solution

    |

  8. Calculate the percentage composition of the elements present in magnes...

    Text Solution

    |

  9. Urea is prepared by the reaction between ammonia and carbon dioxide. ...

    Text Solution

    |

  10. Define oxidation number. What are the rules used to assign oxidation...

    Text Solution

    |

  11. Balance the following equation by oxidation number method C(6)H(6...

    Text Solution

    |

  12. Balance the following equation by oxidation number method. KMNO(4...

    Text Solution

    |

  13. Balance the following equation by oxidation number method. KMnO(4...

    Text Solution

    |

  14. Balancing of molecular equation in alkaline medium. MnO(2)+O(2)+K...

    Text Solution

    |

  15. Explain the steps involved in ion-electron method for balancing redox ...

    Text Solution

    |

  16. Write balanced equation for the oxidation of Ferrous ions to Ferric io...

    Text Solution

    |

  17. A flask A contains 0.5 mole of oxygen gas. Another flask B contains 0....

    Text Solution

    |

  18. Formulate possible compounds of ‘Cl’ in its oxidation state is: 0...

    Text Solution

    |

  19. The Mn^(3+) ion is unstable in solution and undergoes disproportionati...

    Text Solution

    |

  20. Chlorine is used to purify drinking water. Excess of chlorine is harmf...

    Text Solution

    |