Balance the following equation by oxidation number method.
`KMNO_(4)+HClrarrKCl+MnCl_(2)+H_(2)O+Cl_(2)`

Explanation

(ii) `2KMnO_(4)` + 10HC1 `rarr` KCl + `MnCl_(2) + H_(2)O + Cl_(2)`
(iii) Balance the equation atomically (except O and H).
`2KMnO_(4) `+ 10HCl `rarr` 2KCl + `2MnCl_(2) + H_(2)O + Cl_(2)`
(iv) Balance chlorine atoms by adding HCl and multiplying `Cl_(2)` by 5. `2KMnO_(4)` + 16HCl to 2KCl + `2MnCl_(2) + H_(2)O + 5Cl_(2)`
(v) To balance O and H, `H_(2)O` is multiplied by 8.
`2KMnO_(4)` + 16HCl rarr 2KCl + `2MnCl_(2) + 8H_(2)O + 5Cl_(2)` .