Energy of an electron in the ground state of the hydrogen atom is`-2.18 xx 10^(-18)` J. Calculate the ionization enthalpy of atomic hydrogen in terms of J `mol^(-1)`.

Explanation

Energy of an electron in the ground state of the hydrogen atom=`2.18xx10^(-18)J`
`HtoH^(+)+e^(-)`
Energy required to ionize 1 mol e of hydrogen atoms, we multiply by the Avogadro constant.
`E = 2.18 xx 10^(-18) xx 6.023 xx 10^(23)`
= 13.123` xx 10^(5) J mol^(-1)`
I.E = +1312 KJ `mol^(-1)`