Calculate the value of `DeltaU` and `DeltaH` on heating 128.0 g of oxygen from `0^@C` to `100^@C`. CV and `C_p` on an average are 21 and 29 J `"mol"^(-1) K^(-1)` (The difference is `8J "mol"^(-1) K^(-1)` which is approximately equal to R )

Explanation

We know `DeltaU=n C_V(T_2-T_1)`
`DeltaH=n C_P (T_2-T_1)`
Here `n=128/32` 4 moles ,
`T_2=100^@C`=373 K , `T_1=0^@`C =273 K
`DeltaU=nC_V(T_2-T_1)`
`DeltaU` = 4 x 21 x (373-273 )
`DeltaU` =8400 J
`DeltaU` =8.4 kJ
`DeltaH= nC_P (T_2-T_1)`
`DeltaH`=4 x 29 x (373-273)
`DeltaH` =11600 J
`DeltaH`=11.6 kJ