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Calculate the enthalpy of combustion of ...

Calculate the enthalpy of combustion of ethylene at 300K at constant pressure if its enthalpy of combustion at constant volume is `-"1406 kJ mol"^(-1)`.

Text Solution

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The complete ethylene combustion reaction can be written as ,
`C_2H_(4(g)) +3O_(2(g)) to 2CO_(2(g)) +2H_2O_((l))`
`DeltaU`=-1406 kJ
`Deltan=n_(p(g))-n_(r(g))`
`Deltan` =2-4=-2
`DeltaH=DeltaU+RTDeltan_g`
`DeltaH=-1406+8.314xx10^(-3)xx300xx(-2)`
`DeltaH`=-1410.9 kJ
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