The equilibrium constant of a reaction is 10, what will be the sign of `DeltaG` ? Will this reaction be the sign of `DeltaG` ? Will this reaction be spontaneous ?

Explanation

`DeltaG^@`=-2.303 RT log `K_(eq)`
`K_(eq)` =10
`therefore DeltaG^@` =-ve value . So the reaction will be spontaneous .