Suggest and explain an indirect method to calculate lattice enthalpy of sodium chloride crystal.

Explanation

The Born-Haber cycle is used to determine the lattice enthalpy of NaCl as follows:

Formation of NaCl can be considered in 5 steps.
The sum of the enthalpy changes of these steps is equal to the enthalpy change for the overall reaction from which the lattice enthalpy of NaCl is calculated.
`Na_((s)) + 1//2Cl_(2(g)) to NaCl_((s)) " " DeltaH_f^@=-411.3 "kJ mol"^(-1)`
Sublimation : `Na_((s)) to Na_((g)) " " DeltaH_1^0`
Dissociation : `1//2Cl_(2(g)) to Cl_((g)) " " DeltaH_2^0`
Ionisation : `Na_((s)) to Na_((g))^(+) + e^(-) " " DeltaH_3^0`
Electron affinity : `Cl_((g)) + e^(-) to Cl_((g))^(-) " " DeltaH_4^0`
Lattice enthalpy : `Na_((g))^(+) +Cl_((g))^(-) to NaCl_((s)) " " DeltaH_5^0` =?
`DeltaH_f^0=DeltaH_1^0+DeltaH_2^0+Delta_3^0+Delta_4^0+Delta_5^0`
`DeltaH_5^0 =DeltaH_f^0 -(DeltaH_1^0+DeltaH_2^0+DeltaH_3^0+DeltaH_4^0)`
`DeltaH_5^0` = Lattice enthalpy of NaCl .
By the above method , indirectly lattice enthalpy of NaCl is calculated , if the values of `DeltaH_f^0, DeltaH_1^0, DeltaH_2^0,DeltaH_3^0 ` and `DeltaH_4%0` are given.