Calculate the work done when 2 moles of an ideal gas expands reversibly and isothermally from a volume of 500 ml to a volume of 2 L at `25^@C` and normal pressure.

Explanation

Given
n=2 moles
`V_i`=500 ml =0.5 lit
`V_f`=2 lit
`T=25^@C`=298 K
`w=-2.303 nRT log (V_f/V_i)`
`w=-2.303 xx2xx8.314xx298 xxlog (2/0.5)`
w=-2.303 x 2 x 8.314 x 298 x 0.6021
w=-6871 J
w=-6.871 kJ