30.4 kJ is required to melt one mole of sodium chloride. The entropy change during melting is `28.4 JK^(-1) mol^(-1)` . Calculate the melting point of sodium chloride.

Explanation

Given : `DeltaH_f (NaCl)=30.4 kJ =30400 "J mol"^(-1)`
`DeltaS_f (NaCl)=28.4 JK^(-1) mol^(-1)`
`T_f`=?
`DeltaS_f =(DeltaH_f)/(DeltaT_f)`
`T_f =(DeltaH_f)/(DeltaS_f)`
`T_f=(30400 "J mol"^(-1))/(28.4 J K^(-1) "mol"^(-1))`
`T_f` =1070.4 K