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Calculate the amount of heat necessary t...

Calculate the amount of heat necessary to raise 180 g of water from `25^@C` to `100^@C` . Molar heat capacity of water is `75.3 "J mol"^(-1) K^(-1)`

Text Solution

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Given : Number of moles of water `n=(180 g)/(18 g "mol"^(-1))=10` mol molar heat capacity of water
`C_P=75.3 J K^(-1) "mol"^(-1)`
`T_2=100^@C`=373 K
`T_1=25^@C` =298 K
`DeltaH`=?
`DeltaH=nC_P (T_2-T_1)`
`DeltaH="10 mol" xx "75.3 J mol"^(-1) K ^(-1) xx(373-298)K`
`DeltaH`=56475 J
`DeltaH` =56.475 kJ
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