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From the following data at constant volu...

From the following data at constant volume for combustion of benzene, calculate the heat of this reaction at constant pressure condition.
`C_6H_(6(l)) +7 1/2O_(2(g)) to 6CO_(2(g)) +3H_2O_((l))`
`DeltaU` at `25^@C` =-3268.12 kJ

Text Solution

Verified by Experts

Given
`T=25^@C`=298 K
`DeltaU=-3268.12 "kJ mol"^(-1)`
`DeltaH` = ?
`DeltaH=DeltaU+Deltan_gRT`
`DeltaH=DeltaU+(n_p-n_r)RT`
`DeltaH=-3268.12+(6 -7/2)xx8.314xx10^(-3) xx298`
`DeltaU=-3268.12+(2.5xx8.314xx10^(-3)xx298)`
`DeltaU`=-3268.12+6.19
`DeltaU`=-3261.93 kJ `mol^(-1)`
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