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The final temperature of an engine whose...

The final temperature of an engine whose initial temperature 400 K and having efficiency 25% .

A

200 K

B

400 K

C

300 K

D

450 K

Text Solution

Verified by Experts

The correct Answer is:
C
Initial temperature =`T_1`=400 K
Final temperature =`T_2`=?
Efficiency =25%
`eta=[(T_1-T_2)/T_1]xx100`
`25=[(400-T_2)/400]xx100`
`(400-T_2)/4=25`
`400-T_2=100`
`therefore -T_2=100 -400`
`-T_2=-300`
`T_2=300` K
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