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The enthalpy of vaporization of a liquid...

The enthalpy of vaporization of a liquid is `30 kJ "mol"^(-1)` and the entropy of vapourisation `75 JK^(-1) mol^(-1)` .The boiling point of the liquid at 1 atm is ____

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`DeltaH_"vap"=30 kJ "mol"^(-1) xx 1000=30000 "J mol"^(-1)`
`DeltaS_"vap"=75 "J mol"^(-1)`
`T_b`=Boiling point =?
`DeltaS_"vap"=(DeltaH_"vap")/T_b`
`therefore T_b=(DeltaH_"vap")/(DeltaS_"vap")=30000/75`=400 K
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