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The Henry's law constant for two gases A...

The Henry's law constant for two gases A and B are x and y respectively.The ratio of mole fractions of A to B is 0.2 The ratio of mole fraction of B and A dissolved in water will be

A

`(2x )/(y)`

B

`(y)/(0.2y)`

C

`(0.2 x)/(y)`

D

`(5x)/(y)`

Text Solution

Verified by Experts

The correct Answer is:
D

Given, ` (K _(H)) _(A) = x, (K _(H)) =y, (x _(A))/(x _(B)) =0.2 , ((x _(B))/(x _(A)))_("in solution")=` ?
`P _(A) =x (x _(A)) _("in solution")" "...(1)`
`P _(B) =y (x _(B)) _("in solution")" "...(2)`
`((x_(B))/(x_(A))) _(" in solution") = (P_(B))/(P _(A))xx x/y = (x_(B))/(x _(A))xx x/y= (1)/(0.2) xx x/y = (5x)/(y)`
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