The ` K_H` for the solution of oxygen dissolved in water is ` 4xx 10^(4) `atm at a given temperature . If the partial pressure of oxygen in air is 0.4 atm the mole fraction of oxygen in solution is

Options

A. `4.6 xx 10 ^(3)`
B. `1.6 xx 10 ^(4)`
C. `1xx 10^(-5)`
D. `1xx 10 ^(5)`

Answer

C

Explanation

`K _(H) = 4 xx 10^(4) atm, (P _(O_(2)))_(air) = 0.4 atm, (x_(O_(2)))_("in solution")=` ?
`(P _(O_(2)))_(air) = K _(H) (x _(O_(2)))_("in solution ")`
`0.4 =4 xx 10 ^(4) (x _(O_(2)))_("in solution ")`
` therefore (x _(O_(2))) _(" in solution ")= (0.4)/(4 xx 10 ^(4)) =1 xx 10 ^(-5)`