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The relative lowering of vapour pressure...

The relative lowering of vapour pressure of a sugar solution in water is ` 3.5xx 10^(-3) ` The mole fraction of water in that solution is

A

`0.0035`

B

`0.35`

C

`0.0035//18`

D

`0.9965`

Text Solution

Verified by Experts

The correct Answer is:
D

`(Delta P )/(P ^(@))= x _("sugar")`
`3.5 xx 10 ^(-3) =x _("sugar")`
`x _("sugar") + x _(H _(2)O)=1`
`x _(H_(2)O)=1 -0.0035 = 0.9965`
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