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Calculated the molality of a solution c...

Calculated the molality of a solution containing 7.5 g of glycine ` (NH_2 -CH_2 -COOH) ` dissolved in 500g of water

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Molality `= ("No. of moles of solute")/("Mass of solvent (in kg)")`
No. of moles of glycine `=("mass of glycine")/("Molar mass of glycine") = (7.5)/(75) =0.1`
Molality `= ( 0.1)/(0.5 kg) =0.2 m`
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