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Henry's law constant for solubility of m...

Henry's law constant for solubility of methane In benzene is ` 4.2xx 10^(-5) mm` Hg at a particular constant temperature At this temperature calculate the solubility of methane at
(i) 750 mm Hg (ii) 840 mm Hg

Text Solution

Verified by Experts

`(K _(H))_("benzene")= 4.2 xx 10 ^(5) mm Hg,` Solubility of mehhane = ? P = 750 mm Hg. P = 840 mm Hg
According to Henry.s Law.
`P = K _(11) x _("solution")`
750 mm Hg `= 4.2 xx 10 ^(-5) mm HG . x _("solution")`
`implies x _("solution") = (750)/( 4.2 xx 10 ^(-5))` i.e., solubility `= 178.5 xx 10 ^(5)`
Similary at `P = 840 mm Hg`
Solubility `= (840)/( 4.2 xx 10 ^(-5)) = 200 xx 10 ^(-5)`
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