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Vapour pressure of a pure liquid A is 10...

Vapour pressure of a pure liquid A is `10.0` torr at `27^(@)C.` The vapour pressure is lowered to `9.0` torr on dissolving one gram of B in 20g of A. If the molar mass of A is 200 g `mol^(-1)` then calculate the molar mass of B.

Text Solution

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`P _(A)^(@) = 10` torr,` P_("solution") = 9` torr, `W_(A) = 20g, W_(B) =1g, M _(A) =200 g mol ^(-1), M _(B) =` ?
`(Delta P )/(P _(A) ^(@))= (W_(B) xx M _(A))/(M _(B) xx W _(A))`
` (10 -9)/(10) = (1xx 20 0)/( M _(B) xx 20)`
`M _(B) = (200)/(20) xx 10 =100 g mol ^(-1)`
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