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2.56g of Sulphur is dissolved in 100g of...

`2.56g` of Sulphur is dissolved in 100g of carbon disulphide. The solution boils at `319.692 K.` What is the molecular formula of Sulphur in solution? The boiling point of `CS _(2)` is `319.450K.` Given that `K _(b) ` for `CS_(2) = 2.42K kg mol ^(-1)`

Text Solution

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`W_(2)=2.56g`
`W_(1)=100 g`
` T = 319.692K`
`K _(b) = 2.42 K kg mol ^(-1)`
`Delta T_(b) = (319.692-319.450) K = 0.242 K`
`M _(2) = (K_(b)xx W_(2) xx 1000)/(Delta T _(b)xx W_(1))= (2.42 xx2.56 xx 1000)/(0.242 xx 100)`
`M _(2) = 256 g mol ^(-1)`
Molecular mass of sulphur in solution `= 256 g mol ^(-1)`
Atomic mass of one mole of sulphur atom = 32
No. of atoms in a molecule of sulphur `= (256)/(32) =8`
Hence, molecular formula of sulphure is `S_(8),`
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