Home
Class 11
CHEMISTRY
2g of a non electrolyte solute dissolved...

2g of a non electrolyte solute dissolved in 75g of benzene lowered the freezing point of benzene by `0.20` k. The freezing point depression constant of benzene is `5.12 K Kg mol ^(-1).` Find the molar mass of the solute.

Text Solution

Verified by Experts

`W_(2) =2g, W_(1) =75g, Delta T _(f)=0.2 K, k _(f) =5.12 kg mol ^(-1) , M _(2)` = ?
`M _(2) = (K _(f) xx W _(2) xx 1000)/( Delta T_(f) xx W_(1)) = (5.12 xx 2 xx 1000)/( 0.2 xx 75) = 682.66 g mol ^(-1)`
Promotional Banner

Topper's Solved these Questions

  • SOLUTIONS

    FULL MARKS|Exercise ADDITIONAL QUESTIONS SOLVED (CHOOSE THE CORRECT ANSWER)|20 Videos
  • SOLUTIONS

    FULL MARKS|Exercise ADDITIONAL QUESTIONS SOLVED -MATCH THE FOLLOWING|5 Videos
  • SOLUTIONS

    FULL MARKS|Exercise TEXTUAL EVALUATION SOVED - LONG ANSWER QUESTIONS|10 Videos
  • SAMPLE PAPER-8

    FULL MARKS|Exercise Part-IV|10 Videos
  • SOLVED PAPER 03

    FULL MARKS|Exercise PART-IV|10 Videos

Similar Questions

Explore conceptually related problems

1.00 g of a non-electrolyte dissolved in 50.5g of benzene lowered its freezing point by 0.40K. The freezing point depression constant of benzene is "5.12K.kg mol"^(-1) . Find the molecular mass of the solute.

0.900g of a solute was dissolved in 100 ml of benzene at 25^(@)C when its density is 0.879 g/ml. This solution boiled 0.250^(@)C higher than the boiling point of benzene. Molal elevation constant for benzene is "2.52 K.Kg.mol"^(-1) . Calculate the molecular weight of the solute.

15.0g of an unknown molecular material is dissolved in 450g of water. The resulting solution freezes at -0.34^(@)C. What is the molar mass of the material? K_(f) for water = 1.86K kg mol^(-1).

The depression in the freezing point of a benzene solution containing 0.784g of Acetic acid dissolved in 100ml of benzene is 0.35k. Calculate the van.t Hoff factor and the degree of association of the solute at this concentration (k_(f)" for benzene = 5.10 k.kg.mol"^(-1)," molar mass of acetic acid is 60.01").

A 5% solution (by mass) of cane sugar in water has freezing point of 271 K. Calculatge the freezing point of 5% glucose in water if freezing point of pure water is 273.15K

Calculate the mole fraction of benzene and naphthalene in the vapour phase when an ideal liquid solution is formed by mixing 128 g of naphthalene with 39 g of benzene. It is given that the vapour pressure of pure benzene is 50.71 mm Hg and the vapour pressure of pure naphthalene is 32.06 mm Hg at 300 K.