`3.15` g of oxalic acid dihydrate is dissolved in water and the solution was made up to 100 ml using a standard flask. The strength of the solution in normality is ……………

Explanation

`0.5N`
Normality `= ("Number of gram equivalents")/("Volume of the solution in L")`
`= ("Mass of oxalic acid")/(" Equivalent mass of oxalic acid") + ` Volume of the solution in L
`= ((3.15)/(63))/(0.1) = (0.05)/(0.1) =0.5N`