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15.0g of an unknown molecular material i...

`15.0g` of an unknown molecular material is dissolved in 450g of water. The resulting solution freezes at `-0.34^(@)C.` What is the molar mass of the material? `K_(f) for water `= 1.86K kg mol^(-1).`

Text Solution

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`W_(("solvent"))=15.0g`
` W_(("solvent")) =450g`
`Delta T_(f) = T_(1) ^(0) - T_(f) =0-(-0.34)=0.34^(@)C`
`Delta T_(f)= k _(f) m`
`0.34 =1.86 xx (15)/(M) xx (1000)/(450)`
`M = (1.86 xx 15 xx 1000)/(0.34 xx 450) = 182. 35 g mol^(-1).`
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