Home
Class 11
CHEMISTRY
In the molecule O(A) = C = O(B), the fo...

In the molecule `O_(A) = C = O_(B)`, the formal charge on `O_(A)C " and " O_(B)` are respectively.

A

`- 1, 0, + 1`

B

`+ 1, 0,- 1`

C

`- 2,0,+ 2`

D

`0, 0, 0`

Text Solution

Verified by Experts

The correct Answer is:
D


Formal charge of `O_(A)//O_(B) = N_(V) - (N_(e) +(N_(b))/(2))= 6 - (4+(4)/(2))= 6 - 6 = 0`
Formal charge of `C = 4 - (0 + (8)/(2))= 4 - 4 = 0`
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL BONDING

    FULL MARKS|Exercise TEXTUAL EVALUATION SOLVED (SHORT ANSWER QUESTIONS.)|25 Videos
  • CHEMICAL BONDING

    FULL MARKS|Exercise IN TEXT QUESTION-EVALUATE YOURSELF|10 Videos
  • BASIC CONCEPTS OF ORGANIC REACTIONS

    FULL MARKS|Exercise Additional Questions Solved (5-Marks Question)|10 Videos
  • ENVIRONMENTAL CHEMISTRY

    FULL MARKS|Exercise ADDITIONAL QUESTIONS SOLVED ( 5-Mark Questions )|8 Videos

Similar Questions

Explore conceptually related problems

Compound of molecular formula C_(7)H_(8)O is a sweet smelling liquid. A on reaction with acidified K_(2)Cr_(2)O_(7) gives compound B of molecular formula C_(7)H_(8)O . B reduces Tollen's reagent A and B are respectively.

The molecule formula P_(2) O_(5) means that :

Find the value of lambda so that the points P ,Q ,R and S on the sides O A ,O B ,OC and A B , respectively, of a regular tetrahedron O A B C are coplanar. It is given that (O P)/(O A)=1/3,(O Q)/(O B)=1/2,(O R)/(O C)=1/3 and (O S)/(A B)=lambdadot (A) lambda=1/2 (B) lambda=-1 (C) lambda=0 (D) for no value of lambda

Let G_1, G_2a n dG_3 be the centroids of the triangular faces O B C ,O C Aa n dO A B , respectively, of a tetrahedron O A B Cdot If V_1 denotes the volumes of the tetrahedron O A B Ca n dV_2 that of the parallelepiped with O G_1,O G_2a n dO G_3 as three concurrent edges, then prove that 4V_1=9V_1dot

A triangle A B C is inscribed in a circle with centre at O , The lines A O ,B Oa n dC O meet the opposite sides at D , E ,a n dF , respectively. Prove that 1/(A D)+1/(B E)+1/(C F)=(acosA+bcosB+ccosC)/