Draw MO diagram of CO and calculate its bond order .

Explanation

(i) Electronic configuration of C atom: `1s^(2) 2s^(2)2p^(2)`
Electronic configuration of O atom: `1s^(2)2s^(2)2p^(4)`
(ii) Electronic configuration of CO molecule is: `sigma 1s^(2)" " sigma ** 1s^(2)" "sigma2s^(2)" "sigma**2s^(2)" "pi 2p_(y)^(2)" "pi2p_(z)^(2)" "sigma2p_(x)^(2)`
(iii) Bond order `= (N_(b)- N_(a))/(2)(10-4)/(2)=3`
(iv) Molecule has no unpaired electron, hence it is diamagnetic.