Discuss the formation of N2, molecule using MO Theory.

Explanation

(i) Electronic configuration of N atom `1s^(2)2s^(2)2p^(3).`
(ii) Electronic configuration of `N_(2)` molecule is: `sigma1s^(2)" "sigma**1s^(2)" "sigma2s^(2)" "sigma**2s^(2)" "pi2p_(y)^(2)" "pi2p_(z)^(2)" "sigma2p_(x)^(2)`
(iii) Bond order `= (N_(b)-N_(a))/(2)(10-4)/(2)=3`
(iv) Molecule has no unpaired electrons hence, it is diamagnetic.