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Which one of the following has highest b...

Which one of the following has highest bond order? `N_(2), N_(2)^(+) or N_(2)^(-)`?

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`N_(2)` (14 electrons)
Bond order = 3, B.O. = `(N_(b)-N_(a))/(2)=(10-4)/(2)=3`
`N_(2)^(+)` (13 electrons)
Bond order = 2.5, B.O. `=(N_(b)-N_(a))/(2)=(9 - 4)/(2)=2.5`
`N_(2)^(-)` (15 electrons)
Bond order `= 2.5, B.O. = (N_(b)-N_(a))/(2)=(10 -5)/(2)=2.5`
So `N_(2)` has the highest bond order.
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