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0.24 g of organic compound containing ph...

0.24 g of organic compound containing phosphorous gave 0.66 g of `Mg_(2)P_(2)0_(7)` by the usual analysis. Calculate the percentage of phosphorous in the compound

Text Solution

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Weight of an organic compound = 0.24 g
Weight of `Mg_(2)P_(2)0_(7)`= 0.66 g
222 g of `Mg_(2)P_(2)0_(7)` contains= 62 g of P
`"0.66 g contains"=(62)/(222) xx 0.66 "g of P"`
`"Percentage of P"=(62)/(222) xx (0.66)/(0.24) xx 100=76.80%`
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