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0.33g of an organic compound containing ...

0.33g of an organic compound containing phosphorous gave 0.397 g of `Mg_(2)P_(2)0_(7)` by the analysis. Calculate the percentage of P in the compound.

Text Solution

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Weight of organic compound = 0.33g , Weight of `Mg_(2)P_(2)0_(7)`= 0.397g
222 g of `Mg_(2)P_(2)0_(7)` contains 62 g of phosphorous.
`:. 0.397 "g of" Mg_(2)P_(2)0_(7) "will contain" (62)/(222) xx 0.397 "g of P"`.
`0.33 "g of organic compound contains" (62)/(222) xx 0.397 "g of P"`
`:. 100 "g of organic compound will contain" (62)/(222) xx (0.397)/(0.33) xx 100=(2,461.4)/(73.26)=33.59%`
Percentage of phosphorous=33.59%
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