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1 g of an impure sample of magnesium car...

1 g of an impure sample of magnesium carbonate (containing no thermally decomposable impurities) on complete thermal decomposition gave 0.44 g of carbon dioxide gas.To percentage of impurity in the sample is…...........

A

0

B

`4.4%`

C

0.16

D

`8.4%`

Text Solution

Verified by Experts

The correct Answer is:
c
`MgCO_(3)toMgO+CO_(2)uarr`
`MgCO_(3):(1xx24)+(1xx12)+(3xx16)=84 g`
`CO_(2):(1xx12)+(2xx16)=44 g`
100% pure 84 g `MgCO_(3)` on heating gives 44 g `CO_(2)`
Given that 1 g of `MgCO_(3)` on heating gives `0.44 g CO_(2)`
Therefore, 84 g `MgCO_(3)` sample on heating gives `36.96 g CO_(2)=84%`
Percentage of purity of the sample =`(100%)/(44 g CO_(2))xx36.96 g CO_(2)=84%`
Percentage of impurity=16%
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