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Zn((s)) + Cu((aq))^(2+) to Zn((aq))^(2+)...

`Zn_((s)) + Cu_((aq))^(2+) to Zn_((aq))^(2+) + Cu_((s))` . In this reaction, which gets oxidised ?

A

`Cu^(2+)`

B

`Zn^(2+)`

C

Zn

D

`Zn, Cu^(2+)`

Text Solution

Verified by Experts

The correct Answer is:
C
`Zn to Zn^(2+)+2e^(-)`
(loss of electron = oxidation) Zn gets oxidised
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