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The Henry's law constants for two gases ...

The Henry's law constants for two gases A and B are x and y respectively. The ratio of mole fractions of A to B is 0.2. The ratio of mole fraction of B and A dissolved in water will be

A

`(2x)/y`

B

`(y)/(0.2x)`

C

`(0.2x)/(y)`

D

`(5x)/(y)`

Text Solution

Verified by Experts

The correct Answer is:
D
Given , `(K_H)_A = x(K_H)_B = y, (x_A)/(x_B) = 0.2`
`((x_B)/(x_A))_("in solution")= ?`
`P_A = x(x_A)_("in solution")" "…(i)`
`P_B = y(x_(B))_("in solution")" "…(2)`
`((x_B)/(x_A))_("in solution") =(P_B)/(P_A) xx x/y`
`= (x_B)/(x_A) xx x/y =1/(0.2)xx x/y = (5x)/y`
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